10x^2=2x=5

Solution for 10x^2=2x=5 equation:

10x^2=2x=5

We move all terms to the left:

10x^2-(2x)=0

a = 10; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·10·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*10}=\frac{4}{20}
=1/5
$